Mike Dolt Enterprises
Mike Dolt Enterprises
User: calypsomike, Location: 3 Hr 2 Min from Winged Horses
Asked on: Tuesday, March 15, 2011 at 4:24 pm EDT
Answered on: Tuesday, May 14, 2024 at 2:50 am EDT
Question: I took the Low voltage test and missed it by 1 question.In the exam there were 2 waveform drawing questions that I cannot remember the question but the Sine waveforms had both axis's with a ???/divCan anyone help me out on what you think the question might have been and how I would determine the answer ... I know very vague but any help would get me over teh hurdle
Possible Question
Determine the peak-to-peak voltage and frequency of the following sine waveform:^
|||---------------> Time (t)
Axis Labels
Horizontal axis: Time (t) with a scale of ???/div Vertical axis: Voltage with a scale of ???/div
Determining the Answer
1.
Peak-to-Peak Voltage (Vpp)
Count the number of divisions between the positive and negative peaks of the waveform. Multiply this number by the voltage scale (???) to get the peak-to-peak voltage.2.
Frequency (f)
Count the number of complete cycles of the waveform within the given time interval (???/div). Divide the voltage scale (???) by the time scale (???) to convert the divisions to seconds. Divide the number of cycles by the time in seconds to get the frequency in hertz (Hz).
Example Calculation
If the horizontal axis scale is 5 ms/div and the waveform has 3 complete cycles within a 20 ms interval, then: Frequency (f) = (3 cycles) / (20 ms / 5 ms/div) = 3 HzIf the vertical axis scale is 2 V/div, then the waveform has:* Peak-to-Peak Voltage (Vpp) = 10 V (5 divisions x 2 V/div)
Note: The actual values for the voltage scale and time scale will depend on the specific question and your test settings. Flag for review