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Topic: water heater ocpd

User: merle657, Location: 3 Hr 2 Min from Winged Horses

Asked on: Tuesday, March 15, 2011 at 8:06 pm EDT
Answered on: Tuesday, May 14, 2024 at 2:51 am EDT

Question: what is the correct way i would figure ocpd on a water heater with a 3000w and a 6000w on a 240v circuit

Calculating the Overcurrent Protection Circuit (OCPD) for a Water HeaterStep 1: Determine the Amperage (A) Drawn by Each Element

Amperage = Wattage / Voltage Element 1: 3000W / 240V = 12.5A Element 2: 6000W / 240V = 25AStep 2: Determine the Maximum Current (I) Drawn by the Water Heater Since the elements are connected in parallel, the maximum current drawn is the sum of the individual element currents. I = 12.5A + 25A = 37.5AStep 3: Determine the OCPD Rating The OCPD rating should be at least 125% of the maximum current drawn. OCPD Rating = 125% x I OCPD Rating = 125% x 37.5A = 46.88ANote

The OCPD rating should be rounded up to the nearest standard circuit breaker or fuse size, which is typically 50A.* Therefore, the correct OCPD rating for this water heater is

50A
.

Conclusion

The overcurrent protection circuit (OCPD) for this water heater with a 3000W and a 6000W element on a 240V circuit should be rated for

50A
. Flag for review

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