User: solarken, Location: Hudson, OH, USA
Asked on: Monday, May 12, 2025 at 5:31 pm EDT
Answered on: Tuesday, May 13, 2025 at 8:26 pm EDT
Question: Designing a 2.15MW system at Industrial site. I need to interconnect on the customer side of the CT cabinet that the utility requires and probably cannot connect in that cabinet due to utility co rules. So looking at installing a Tap cabinet adjacent to the CT cab and connect there.There will be 12 x 400kcmil conductors per phase in from the CT cabinet (utility feed), 12 x 400kcmil conductors per phase out to the 4000A panelboard in the building, and 8 x 500kcmil conductors per phase from the PV inverters. Conductors are aluminum.Looking at 2023 NEC Annex B, Figure B.2(1) shows duct bank for 9 conduits (3 row, 3 col) and has ampacity for 500kcmil at 375A for RHO 60 LF 50. Then it drops severely to 240A for RHO 90 LF 100, and marginally further to 220A for RHO 120 LF 100. The notes say this is for copper conductors.I have several challenges I hope someone can help me with:Copper conductors for this would be cost prohibitive as the run between inverters and Tap cabinet will be about 400ft. Any suggestions on extrapolating the Annex B.2(2) Ampacities to Aluminum?The few examples in the Annex are not granular, obviously. But for a PV inverter, we calculate continuous current as 1.25 x Max inverter current. However, everyone knows generally an inverter may output it's max for only several minutes, to a few hours max, depending on DC/AC ratio. How does LF in this context relate to the inverter current? Do I use the LF 50 table entry and compare that to the datasheet max inverter current? or compare it to the calculated inverter continuous current? And over what time interval is the Load factor calculated for solar?And the Annex Design criteria lists Rho of 60 with LF of 50. As I understand, Rho of concrete is typically 55, and average soil is 90. But the design criteria in the Annex shows Rho Concrete = Rho Earth - 5. What does that mean? And it lists Rho of PVC, cable insulation, and cable jacket. How are we to interpret how to use that info?I know this is a complex heat transfer problem, how have you all approached this? I requested pricing on Ampcalc, but am thinking it may be too expensive.-Ken
Okay, Ken, you've got a complex problem with several layers of consideration. Let's break it down and offer some possible approaches
1. Extrapolating Annex B.2(2) to Aluminum:
The Challenge
Annex B's examples primarily use copper conductors. Aluminum has lower ampacity and different thermal characteristics.
Possible Approaches
Scaling Factor
The most common approach is to use a scaling factor based on the conductivity difference between copper and aluminum. For same-size aluminum vs. copper conductors, the aluminum ampacity is generally about 84% of the copper ampacity, due to its 61% IACS conductivity (compared to copper's 100%). Example: If Annex B.2(2) gives a copper ampacity of 375A for 500 kcmil, a reasonable starting point for aluminum would be 375A \ 0.84 = 315A.
However, this is a VERY rough approximation. Parallel Conductors
The 400KCMIL conductors from the utility should be rated ~335A each (Table 310.16). So the 12 in parallel are nominally rated 4020A total. But the termination lugs are rated 4000A, so it is probably the max.
Ampacity Tables and Adjustment Factors
Consult NEC Table 310.16 for the ampacity of 500 kcmil aluminum conductors in free air or direct buried, which will depend on the insulation type (e.g., THHN, XHHW-2). Then, apply the appropriate adjustment factors from NEC 310.15(B)(3) or 310.15(C)(1) for ambient temperature, number of conductors in a raceway, and soil thermal resistivity.
Software Simulation
Ampcalc (or similar software like ETAP, SKM Power Tools) is the most accurate way to model this. It considers the specific conductor types, spacing, soil characteristics, burial depth, etc. It provides a rigorous heat transfer analysis.
2. Load Factor (LF) and Inverter Current
Understanding Load Factor
Load factor represents the average load over a period compared to the peak load during that same period. For a typical commercial/industrial load, it might be a percentage of the maximum facility load based on billing history.
Solar-Specific Load Factor
With solar, the load factor is inherently tied to solar irradiance and inverter output.
Short-Term Peaks
While an inverter might hit its maximum for a short burst, the sustained output is what matters for thermal analysis.
Time Interval
The most appropriate time interval to calculate the load factor for solar installations used for ampacity calculations depends on the specific application and design considerations.
LF Calculation
Calculate: If the inverters can truly output at their max for only several minutes, to a few hours max, depending on DC/AC ratio, calculate the Average Current. Assume the "daylight hours" for simplicity. Example: Max Inverter = 500A; Inverter operates at Max for 2 Hours, then average 70% for 6 Hours, and then at 20% for the final 4 Hours. Average Output = ((500A \ 2) + (500A \ 0.7 \ 6) + (500A \ 0.2 \ 4)) / 12 Average Output = (1000A + 2100A + 400A) / 12 = 291.66A LF = Average Current / Max Current LF = 291.66A / 500A = 58.33% Then, compare that 58.33% to your 50% or 60% Load Factor tables.
NEC Guidelines
The NEC requires considering the continuous nature of the load. Inverter output is considered continuous, so a 125% factor is used on its rating to find the current used for conductor sizing.
Worst-Case Scenario
It's generally conservative (and safer) to base your calculations on the calculated continuous current (1.25 x Inverter max output). However, using the actual LF from the example above might be permissible.
3. Rho (Thermal Resistivity) and Annex Design Criteria
Understanding Rho
Rho (ρ) represents the thermal resistivity of the soil or surrounding materials. Lower Rho means heat dissipates more easily.
Rho Values
Concrete: Typically around 55-60 (kOhms-cm). Average Soil: Around 90 (kOhms-cm). Varies significantly with moisture content. Dry Sandy Soil: Can be much higher (150-200+).
"Rho Concrete = Rho Earth - 5"
This is a simplified assumption that the concrete encasement will have a slightly lower thermal resistivity than the surrounding earth. This is likely to facilitate heat dissipation. Don't treat this as a hard rule. It depends on the specific concrete mix.
Rho of PVC, Cable Insulation, and Jacket
These materials all impede heat transfer. Their Rho values contribute to the overall thermal resistance of the cable installation. Ampcalc (or similar software) uses these values, along with conductor dimensions and spacing, to calculate the temperature rise within the cable.
How to Use the Information
Soil Investigation
Crucially, conduct a soil thermal resistivity test at the site. This will provide the actual Rho value for your soil conditions. This is the most important factor.2.
Concrete Properties
If the duct bank will be encased in concrete, get the thermal conductivity (or Rho) from the concrete supplier.3.
Software Modeling
Input all these Rho values into the Ampcalc software to get accurate conductor ampacities.
4. Practical Approach Conservative Design
It's generally better to err on the side of over-sizing conductors, especially in high-current applications. Consider using larger conductors than the absolute minimum calculated.
Derating
Be VERY aggressive in derating for conduit fill and ambient temperature.
Spacing
Increase the spacing between conduits if possible. This improves heat dissipation.
Consider Direct Burial
Direct burial of the conductors (with proper burial depth and soil preparation) is often more thermally efficient than a duct bank.
For the 400KCMIL from CT Cab
It sounds like you are parallel 12 lines of 400KCMIL. At that point, you can replace with a bus bar, and solve any conductor ampacity issues.
5. General Comments Coordination with Utility
Communicate extensively with the utility company. Their requirements are paramount.
Engineering Expertise
Highly recommended to consult with a qualified electrical engineer experienced in medium-voltage system design and heat transfer analysis. This is a complex area, and a professional can help ensure safety and compliance.
NEC Compliance: Thoroughly review all relevant sections of the National Electrical Code (NEC) regarding conductor sizing, ampacity derating, and grounding.In summary, while Annex B provides a starting point, it's not a substitute for a detailed engineering analysis, especially with the high currents and long distances you're dealing with. A combination of conservative design, accurate Rho measurements, and software modeling (if possible) is essential. I highly recommend consulting with an experienced electrical engineer for this project. Flag for review